wave_mechanics Beats Question 10
Question: Two tuning forks of frequencies 256 and 258 vibrations/sec are sounded together, then time interval between consecutive maxima heard by the observer is
[MP PET/PMT 1988]
Options:
A) 2 sec
B) 0.5 sec
C) 250 sec
D) 252 sec
Show Answer
Answer:
Correct Answer: B
Solution:
$ T=\frac{1}{258-256} $ = $ 0.5\sec $
BETA
