wave_mechanics Beats Question 39
Question: The wavelength of a particle is 99 cm and that of other is 100 cm. Speed of sound is 396 m/s. The number of beats heard is
[DCE 2001]
Options:
A) 4
B) 5
C) 1
D) 8
Show Answer
Answer:
Correct Answer: A
Solution:
$ \Delta n=v[ \frac{1}{{\lambda _{1}}}-\frac{1}{{\lambda _{2}}} ]=396[ \frac{1}{0.99}-\frac{1}{1} ]=3.96\approx 4.
$
BETA
