wave_mechanics Beats Question 41

A tuning fork vibrates with 2 beats in 0.04 second. The frequency of the fork is 50 Hz

[AFMC 2003]

Options:

A) 50 Hz

B) 100 Hz

C) 80 Hz

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

Frequency = $ \frac{\text{Number of beats}}{\text{Time}}=\frac{2}{0.04}=50Hz $



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