Wave Mechanics Vibration Of String Question 16
Question: Frequency of a sonometer wire is n. Now its tension is increased 4 times and its length is doubled then new frequency will be
[RPET 2000]
Options:
A) n/2
B) 4n
C) 2n
D) n
Show Answer
Answer:
Correct Answer: D
Solution:
$ n\propto \frac{1}{l}\sqrt{T} $
Therefore $ \frac{{{n}’}}{n}=\sqrt{\frac{{{T}’}}{T}}\times \frac{l}{{{l}’}}=\sqrt{4}\times \frac{1}{2}=1 $
Therefore $ {n}’=n $