Wave Mechanics Vibration Of String Question 16

Question: Frequency of a sonometer wire is n. Now its tension is increased 4 times and its length is doubled then new frequency will be

[RPET 2000]

Options:

A) n/2

B) 4n

C) 2n

D) n

Show Answer

Answer:

Correct Answer: D

Solution:

$ n\propto \frac{1}{l}\sqrt{T} $

Therefore $ \frac{{{n}’}}{n}=\sqrt{\frac{{{T}’}}{T}}\times \frac{l}{{{l}’}}=\sqrt{4}\times \frac{1}{2}=1 $

Therefore $ {n}’=n $