wave_mechanics critical_thinking Question 41
Question: A string of length L and mass M hangs freely from a fixed point. Then the velocity of transverse waves along the string at a distance x from the free end is
Options:
A) $ \sqrt{gL} $
B) $ \sqrt{gx} $
C) $ gL $
D) $ gx $
Show Answer
Answer:
Correct Answer: B
Solution:
Velocity $ v=\sqrt{\frac{T}{m}} $ ; where $ T= $ weight of part of rope hanging below the point under consideration $ =( \frac{M}{L} )xg $
Therefore $ v=\sqrt{\frac{( \frac{M}{L} )xg}{( \frac{M}{L} )}}=\sqrt{xg} $ .
BETA
