wave_mechanics dopplers_effect Question 17

Question: A sound source is moving towards a stationary observer with 1/10 of the speed of sound. The ratio of apparent to real frequency is

[CPMT 1977; NCERT 1977; KCET 2001, 03]

Options:

A) 10/9

B) 11/10

C) $ {{(11/10)}^{2}} $

D) $ {{(9/10)}^{2}} $

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Answer:

Correct Answer: A

Solution:

$ n’=n( \frac{v}{v-v _{S}} )=n( \frac{v}{v-v/10} ) $

Therefore $ \frac{n’}{n}=\frac{10}{9} $