wave_mechanics dopplers_effect Question 30
Question: A whistle giving out 450 Hz approaches a stationary observer at a speed of 33 m/s. The frequency heard by the observer in Hz is
[IIT 1997 Cancelled]
Options:
A) 409
B) 429
C) 517
D) 500
Show Answer
Answer:
Correct Answer: D
Solution:
The apparent frequency heard by the observer is given by $ n’=\frac{v}{v-v _{S}}n $ = $ \frac{330}{330-33}\times 450=\frac{330}{297}\times 450=500 $
$ Hz $
BETA
