wave_mechanics dopplers_effect Question 51

Question: A car sounding a horn of frequency 1000 Hz passes an observer. The ratio of frequencies of the horn noted by the observer before and after passing of the car is 11 : 9. If the speed of sound is v, the speed of the car is

[MP PET 2002]

Options:

A) $ \frac{1}{10}v $

B) $ \frac{1}{2}v $

C) $ \frac{1}{5}v $

D) v

Show Answer

Answer:

Correct Answer: A

Solution:

$ n _{Before}=\frac{v}{v-v _{c}}n $ and $ n _{After}=\frac{v}{v+v _{c}}.n $

$ \frac{n _{Before}}{n _{After}}=\frac{11}{9}=( \frac{v+v _{c}}{v-v _{c}} ) $

Therefore $ v _{c}\Rightarrow \frac{v}{10} $