wave_mechanics interference_and_superposition_of_waves Question 2
Question: When two sound waves with a phase difference of $ \pi /2 $ , and each having amplitude A and frequency $ \omega $ , are superimposed on each other, then the maximum amplitude and frequency of resultant wave is
[MP PMT 1989]
Options:
A) $ \frac{A}{\sqrt{2}}:\frac{\omega }{2} $
B) $ \frac{A}{\sqrt{2}}:\omega $
C) $ \sqrt{2}A:\frac{\omega }{2} $
D) $ \sqrt{2}A:\omega $
Show Answer
Answer:
Correct Answer: D
Solution:
$ {A _{\max }}=\sqrt{A^{2}+A^{2}}=A\sqrt{2}, $ frequency will remain same i.e.
w.
BETA
