wave_mechanics interference_and_superposition_of_waves Question 4

Question: The superposition takes place between two waves of frequency f and amplitude a. The total intensity is directly proportional to

[MP PMT 1986]

Options:

A) a

B) 2a

C) $ 2a^{2} $

D) $ 4a^{2} $

Show Answer

Answer:

Correct Answer: D

Solution:

Resultant amplitude $ A=\sqrt{a^{2}+a^{2}+2aa\cos \varphi } $

$ =\sqrt{4a^{2}{{\cos }^{2}}( \frac{\varphi }{2} )} $

$ \because $

$ n=\frac{pv}{2l} $

Therefore $ I\propto 4a^{2} $