wave_mechanics interference_and_superposition_of_waves Question 4
Question: The superposition takes place between two waves of frequency f and amplitude a. The total intensity is directly proportional to
[MP PMT 1986]
Options:
A) a
B) 2a
C) $ 2a^{2} $
D) $ 4a^{2} $
Show Answer
Answer:
Correct Answer: D
Solution:
Resultant amplitude $ A=\sqrt{a^{2}+a^{2}+2aa\cos \varphi } $
$ =\sqrt{4a^{2}{{\cos }^{2}}( \frac{\varphi }{2} )} $
$ \because $
$ n=\frac{pv}{2l} $
Therefore $ I\propto 4a^{2} $