wave_mechanics interference_and_superposition_of_waves Question 10
Question: Two sound waves (expressed in CGS units) given by $ y _{1}=0.3\sin \frac{2\pi }{\lambda }(vt-x) $ and $ y _{2}=0.4\sin \frac{2\pi }{\lambda }(vt-x+\theta ) $ interfere. The resultant amplitude at a place where phase difference is $ \pi /2 $ will be
[MP PET 1991]
Options:
A) 0.7 cm
B) 0.1 cm
C) 0.5 cm
D) $ \frac{1}{10}\sqrt{7}cm $
Show Answer
Answer:
Correct Answer: C
Solution:
Resultant amplitude = $ \sqrt{a _{1}^{2}+a _{2}^{2}+2a _{1}a _{2}\cos \varphi } $ = $ \sqrt{{{0.3}^{2}}+{{0.4}^{2}}+2\times 0.3\times 0.4\times \cos \frac{\pi }{2}} $ = $ 0.5cm $
BETA
