wave_mechanics interference_and_superposition_of_waves Question 16
Question: The displacement of a particle is given by $ x=3\sin (5\pi t)+4\cos (5\pi t) $ The amplitude of the particle is
[MP PMT 1999]
Options:
A) 3
B) 4
C) 5
D) 7
Show Answer
Answer:
Correct Answer: C
Solution:
For the given super imposing waves $ a _{1}=3, $
$ a _{2}=4 $ and phase difference $ \varphi =\frac{\pi }{2} $
Therefore $ A=\sqrt{a _{1}^{2}+a _{2}^{2}+2a _{1}a _{2}\cos \pi /2}=\sqrt{{{(3)}^{2}}+{{(4)}^{2}}}=5 $
BETA
