wave_mechanics interference_and_superposition_of_waves Question 18
Question: If the ratio of amplitude of wave is 2 : 1, then the ratio of maximum and minimum intensity is
[MH CET 1999]
Options:
A) 9 : 1
B) 1 : 9
C) 4 : 1
D) 1 : 4
Show Answer
Answer:
Correct Answer: A
Solution:
$ \frac{{I _{\max }}}{{I _{\min }}}={{( \frac{\frac{a _{1}}{a _{2}}+1}{\frac{a _{1}}{a _{2}}-1} )}^{2}}={{( \frac{2+1}{2-1} )}^{2}}=9/1 $
BETA
