wave_mechanics interference_and_superposition_of_waves Question 20
Question: If the ratio of amplitude of two waves is 4 : 3. Then the ratio of maximum and minimum intensity will be
[MHCET 2000]
Options:
A) 16 : 18
B) 18 : 16
C) 49 : 1
D) 1 : 49
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{{I _{\max }}}{{I _{\min }}}={{( \frac{\frac{a _{1}}{a _{2}}+1}{\frac{a _{1}}{a _{2}}-1} )}^{2}}={{( \frac{\frac{4}{3}+1}{\frac{4}{3}-1} )}^{2}}=\frac{49}{1} $
BETA
