wave_mechanics interference_and_superposition_of_waves Question 21
Question: Equation of motion in the same direction is given by $ y _{1}=A\sin (\omega t-kx) $ , $ y _{2}=A\sin (\omega t-kx-\theta ) $ . The amplitude of the medium particle will be
[BHU 2003]
Options:
A) $ 2A\cos \frac{\theta }{2} $
B) $ 2A\cos \theta $
C) $ \sqrt{2}A\cos \frac{\theta }{2} $
D) $ 1.2f,\ 1.2\lambda $
Show Answer
Answer:
Correct Answer: A
Solution:
The resultant amplitude is given by $ A _{R}=\sqrt{A^{2}+A^{2}+2AA\cos \theta }=\sqrt{2A^{2}(1+\cos \theta )} $
$ =2A\cos \theta /2 $
$ {n}’=2n $
BETA
