wave_mechanics interference_and_superposition_of_waves Question 23
Question: The displacement of the interfering light waves are $ y _{1}=4\sin \omega t $ and $ y _{2}=3\sin ( \omega t+\frac{\pi }{2} ) $ . What is the amplitude of the resultant wave
[RPMT 1996; Orissa JEE 2005]
Options:
A) 5
B) 7
C) 1
D) 0
Show Answer
Answer:
Correct Answer: A
Solution:
Since $ \varphi =\frac{\pi }{2} $
Therefore $ A=\sqrt{a _{1}^{2}+a _{2}^{2}}=\sqrt{{{(4)}^{2}}+{{(3)}^{2}}}=5 $
BETA
