wave_mechanics mock_test_waves_and_acoustics Question 2

Question: An open pipe is in resonance in its $ 2^{nd} $ harmonic with tuning fork of frequency$ f _{1} $ . Now it is closed at one end. If the frequency of the tuning fork is increased slowly from $ f _{1} $ then again a resonance is obtained with a frequency$ f _{2} $ . If in this case the pipe vibrates $ n^{th} $ harmonics then

Options:

A) $ n=3,f _{2}=\frac{3}{4}f _{1} $

B) $ n=3,f _{2}=\frac{5}{4}f _{1} $

C) $ n=5,f _{2}=\frac{5}{4}f _{1} $

D) $ n=5,f _{2}=\frac{3}{4}f _{1} $

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Answer:

Correct Answer: C

Solution:

[c] Open pipe resonance frequency $ f _{1}=\frac{2v}{2L} $ Closed pipe resonance frequency$ f _{2}=\frac{nv}{4L} $

$ f _{2}=\frac{n}{4}f _{1} $ (Where n is odd and$ f _{2}>f _{1} $ ) $ \therefore n=5 $