wave_mechanics organ_pipe_vibration_of_air_column Question 23
Question: If v is the speed of sound in air then the shortest length of the closed pipe which resonates to a frequency n
[KCET 2003]
Options:
A) $ \frac{v}{4n} $
B) $ \frac{v}{2n} $
C) $ \frac{2n}{v} $
D) $ \frac{4n}{v} $
Show Answer
Answer:
Correct Answer: A
Solution:
For shortest length of pipe mode of vibration must be fundamental i.e., $ n=\frac{v}{4l} $
Therefore $ l=\frac{v}{4n}.
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BETA
