wave_mechanics organ_pipe_vibration_of_air_column Question 39
Question: Fundamental frequency of an open pipe of length 0.5 m is equal to the frequency of the first overtone of a closed pipe of length l. The value of lc is (m)
[KCET 1999]
Options:
A) 1.5
B) 0.75
C) 2
D) 1
Show Answer
Answer:
Correct Answer: B
Solution:
First tone of open pipe = first overtone of closed pipe
Therefore $ \frac{v}{2l _{0}}=\frac{3v}{4l _{c}} $
Therefore $ l _{c}=\frac{3\times 2\times 0.5}{4}=0.75m $