wave_mechanics organ_pipe_vibration_of_air_column Question 39

Question: Fundamental frequency of an open pipe of length 0.5 m is equal to the frequency of the first overtone of a closed pipe of length l. The value of lc is (m)

[KCET 1999]

Options:

A) 1.5

B) 0.75

C) 2

D) 1

Show Answer

Answer:

Correct Answer: B

Solution:

First tone of open pipe = first overtone of closed pipe

Therefore $ \frac{v}{2l _{0}}=\frac{3v}{4l _{c}} $

Therefore $ l _{c}=\frac{3\times 2\times 0.5}{4}=0.75m $



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