wave_mechanics organ_pipe_vibration_of_air_column Question 45
Question: In a resonance tube the first resonance with a tuning fork occurs at 16 cm and second at 49 cm. If the velocity of sound is 330 m/s, the frequency of tuning fork is
[DPMT 2002]
Options:
A) 500
B) 300
C) 330
D) 165
Show Answer
Answer:
Correct Answer: A
Solution:
For closed pipe $ l _{1}=\frac{v}{4n} $ ;$ l _{2}=\frac{3v}{4n} $
Therefore $ v=2n(l _{2}-l _{1}) $
Therefore $ n=\frac{v}{2(l _{2}-l _{1})}=\frac{330}{2\times (0.49-0.16)}=500Hz $
BETA
