wave_mechanics organ_pipe_vibration_of_air_column Question 53
Question: An open tube is in resonance with string (frequency of vibration of tube is n0). If tube is dipped in water so that 75% of length of tube is inside water, then the ratio of the frequency of tube to string now will be
[J & K CET 2005]
Options:
A) 1
B) 2
C) $ \frac{2}{3} $
D) $ \frac{3}{2} $
Show Answer
Answer:
Correct Answer: B
Solution:
For open tube, $ n _{0}=\frac{v}{2l} $ For closed tube length available for resonance is $ l’=l\times \frac{25}{100}=\frac{l}{4} $ \ Fundamental frequency of water filled tube $ n=\frac{v}{4l’}=\frac{v}{4\times (l/4)}=\frac{v}{l}=2n _{0} $
Therefore $ \frac{n}{n _{0}}=2 $
BETA
