Wave Mechanics Stationary Waves Question 39
Question: A string vibrates according to the equation $ y=5\sin ( \frac{2\pi x}{3} )\cos 20\pi t $ , where x and y are in cm and t in sec. The distance between two adjacent nodes is
[UPSEAT 2005]
Options:
A) 3 cm
B) 4.5 cm
C) 6 cm
D) 1.5 cm
Show Answer
Answer:
Correct Answer: D
Solution:
$ y=5\sin ( \frac{2\pi x}{3} )\cos 20\pi t, $ comparing with equation $ y=2a\sin \frac{2\pi x}{\lambda }\cos \frac{2\pi vt}{\lambda } $
Therefore $ \lambda =3, $ distance between two adjacent nodes $ =\lambda /2=1.5cm $ .
BETA
