Physics And Measurement Question 291
Question: In a simple pendulum experiment, the maximum percentage error in the measurement of length is 2% and that in the observation of the time- period is 3%. Then the maximum percentage error in determination of the acceleration due to gravity g is
Options:
A) 5%
B) 6%
C) 1%
D) 8%
Show Answer
Answer:
Correct Answer: D
Solution:
[d] As we know, time period of a simple pendulum
$ T=2\pi \sqrt{\frac{L}{g}\Rightarrow g=\frac{4{{\pi }^{2}}L}{T^{2}}} $
The maximum percentage error in g $ \frac{\Delta g}{g}\times 100=\frac{\Delta L}{L}\times 100+2( \frac{\Delta T}{T}\times 100 ) $
$ =2$%$+2(3$%$)=8$%
BETA
