[J & K CET 2004]
A) $ m/kg\text{-}s $
B) $ m\text{-}s/kg^{2} $
C) $ kg/m\text{-}s^{2} $
D) $ kg/m\text{-}s $
Correct Answer: D
$ [\eta ]=M{{L}^{-1}}{{T}^{-1}} $ so its unit will be kg/m-sec.
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