Physics And Measurement Question 69
Question: The dimensions of Farad are
[MP PET 1993]
Options:
A) $ {{M}^{-1}}{{L}^{-2}}T^{2}Q^{2} $
B) $ {{M}^{-1}}{{L}^{-2}}TQ $
C) $ {{M}^{-1}}{{L}^{-2}}{{T}^{-2}}Q $
D) $ {{M}^{-1}}{{L}^{-2}}TQ^{2} $
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Answer:
Correct Answer: A
Solution:
Farad is the unit of capacitance and $ C=\frac{Q}{V} $ = $ \frac{[Q]}{[ML^{2}{{T}^{-2}}{{Q}^{-1}}]} $ = $ {{M}^{-1}}{{L}^{-2}}T^{2}Q^{2} $
BETA
