Physics And Measurement Question 211
Question: The pitch and the number of circular scale divisions in a screw gauge with least count 0.02 mm are respectively
Options:
A) 1mm and 100
B) 0.5 mm and 50
C) 1 mm and 50
D) 0.5 mm and 100
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Least count of a screw gauge
$ =\frac{Pitch}{Numberofcircularscaledivisions} $
$ =\frac{1mm}{50}=0.02mm $
Therefore the pitch and no. of circular scale divisions are 1mm and 50 respectively.
BETA
