Physics And Measurement Question 182
Question: If there is a positive error of 50% in the measurement of velocity of a body, then the error in the measurement of kinetic energy is
Options:
A) 25%
B) 50%
C) 100%
D) 125%
Show Answer
Answer:
Correct Answer: D
Solution:
Kinetic energy $ E=\frac{1}{2}mv^{2} $
$ \therefore \frac{\Delta E}{E}\times 100=\frac{{{{{v}’}}^{2}}-v^{2}}{v^{2}}\times 100 $
$ =[{{(1.5)}^{2}}-1]\times 100 $
$ \therefore \frac{\Delta E}{E}\times 100=125$ %
BETA
