Physics And Measurement Question 222
Question: Young’s modulus of steel is $ 1.9\times 10^{11}N/m^{2} $ . When expressed in CGS units of $ dyne/cm^{2} $ , it will be equal to ( $ (1N=10^{5}dyne,1m^{2}=10^{4}cm^{2}) $
Options:
A) $ 1.9\times 10^{10} $
B) $ 1.9\times 10^{11} $
C) $ 1.9\times 10^{12} $
D) $ 1.9\times 10^{13} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] It is given that Young’s modulus (Y) is, $ Y=1.9\times 10^{11}N/m^{2} $
$ 1N=10^{5}dyne $
$ So,Y=1.9\times 10^{11}\times 10^{5}dyne/m^{2} $
Convert meter to centimeter $ \because 1m=100cm $
$ Y=1.9\times 10^{11}\times 10^{5}dyne/{{(100)}^{2}}cm^{2} $
$ =1.9\times 10^{12}dyne/cm^{2} $
BETA
