Physics And Measurement Question 254
Question: A quantity X is given by $ {\varepsilon _{0}}L\frac{\Delta V}{\Delta t} $ where $ {\in _{0}} $ is the permittivity of the free space, L is a length, $ \Delta V $ is a potential difference and $ \Delta t $ is a time interval. The dimensional formula for X is the same as that of
Options:
A) Resistance
B) charge
C) Voltage
D) current
Show Answer
Answer:
Correct Answer: D
Solution:
[d] Dimensionally $ {\varepsilon _{0}}L=C $ where C= capacitance Now the given expression reduces to $ C\Delta V/\Delta t. $ Dimensionally $ C\Delta V=q $ where q is charge. Again the given expression reduces to $ q/\Delta t. $ Dimensionally $ \frac{q}{\Delta t}=I $ where I is current
BETA
