Physics Elasticity Question 42
Question: A cube of aluminium of sides 0.1 m is subjected to a shearing force of 100 N. The top face of the cube is displaced through 0.02 cm with respect to the bottom face. The shearing strain would be
Options:
A) 0.02
B) 0.1
C) 0.005
D) 0.002
Show Answer
Answer:
Correct Answer: D
Solution:
Shearing strain $ \varphi =\frac{x}{L}=\frac{0.02cm}{10cm} $ \ $ \varphi =0.002 $
BETA
