Physics Elasticity Question 132
Question: A wire of cross-sectional area $ 3,mm^{2} $ is first stretched between two fixed points at a temperature of 20°C. Determine the tension when the temperature falls to 10°C. Coefficient of linear expansion $ \alpha ={{10}^{-5}}{}^\circ {{C}^{-1}} $ and $ Y=2\times 10^{11},N/m^{2} $
[EAMCET 1994]
Options:
A) 20 N
B) 30 N
C) 60 N
D) 120 N
Show Answer
Answer:
Correct Answer: C
Solution:
$ F=YA\alpha \Delta t $
$ =2\times 10^{11}\times 3\times {{10}^{-6}}\times {{10}^{-5}}\times (20-10)=60N $
BETA
