Physics Elasticity Question 137
Question: A rod is fixed between two points at 20°C. The coefficient of linear expansion of material of rod is $ 1.1\times {{10}^{-5}}/{}^\circ C $ and Young’s modulus is $ 1.2\times 10^{11},N/m $ . Find the stress developed in the rodif temperature of rod becomes 10°C
[RPET 1997]
Options:
A) $ 1.32\times 10^{7},N/m^{2} $
B) $ 1.10\times 10^{15},N/m^{2} $
C) $ 1.32\times 10^{8},N/m^{2} $
D) $ 1.10\times 10^{6},N/m^{2} $
Show Answer
Answer:
Correct Answer: A
Solution:
Thermal stress =$ Y\alpha \Delta \theta $
$ =1.2\times 10^{11}\times 1.1\times {{10}^{-5}}\times (20-10) $
$ =1.32\times 10^{7}\ N/m^{2} $
BETA
