Physics Elasticity Question 139
Question: A rubber pipe of density $ 1.5\times 10^{3},N/m^{2} $ and Young’s modulus $ 5\times 10^{6},N/m^{2} $ is suspended from the roof. The length of the pipe is 8 m. What will be the change in length due to its own weight
[RPET 1996]
Options:
A) 9.6 m
B) $ 9.6\times 10^{3},m $
C) $ 19.2\times {{10}^{-2}},m $
D) $ 9.6\times {{10}^{-2}},m $
Show Answer
Answer:
Correct Answer: D
Solution:
$ l=\frac{L^{2}dg}{2Y} $
$ =\frac{{{(8)}^{2}}\times 1.5\times 10^{3}\times 10}{2\times 5\times 10^{6}}=9.6\times {{10}^{-2}}m $
BETA
