Physics Elasticity Question 44
Question: The upper end of a wire of radius 4 mm and length 100 cm is clamped and its other end is twisted through an angle of$ 30{}^\circ $ . Then angle of shear is
[NCERT 1990; MP PMT 1996]
Options:
A) $ 12{}^\circ $
B) $ 0.12{}^\circ $
C) $ 1.2{}^\circ $
D) $ 0.012{}^\circ $
Show Answer
Answer:
Correct Answer: B
Solution:
Angle of shear$ \varphi =\frac{r\theta }{L} $
$ =\frac{4\times {{10}^{-1}}}{100}\times 30^{o}={{0.12}^{o}} $
BETA
