Physics Elasticity Question 148
On applying a stress of $ 20\times 10^{8} $ N/$ m^{2} $ the length of a perfectly elastic wire is doubled. Its Young’s modulus will be
[MP PET 2000]
Options:
A) $ 40\times 10^{8}N/m^{2} $
B)$ 20\times 10^{8}N/m^{2} $
C) $ 10\times 10^{8}N/m^{2} $
D)$ 5\times 10^{8}N/m^{2} $
Show Answer
Answer:
Correct Answer: B
Solution:
Young’s modulus =$ \frac{F}{A} $ As the length of wire gets doubled
Therefore strain = 1 Y = strain = 20 ×10^8 N/m²
BETA
