Physics Elasticity Question 155

Question: A uniform plank of Young’s modulus Y is moved overa smooth horizontal surface by a constant horizontal force F. The area of cross section of the plank is A. The compressive strain on the plank in the direction of the force is

[Kerala PET 2002]

Options:

A) $ F/AY $

B)$ 2F/AY $

C) $ \frac{1}{2}(F/AY) $

D)$ 3F/AY $

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Answer:

Correct Answer: A

Solution:

$ Y=\frac{F/A}{r}\Rightarrow r=\frac{F}{Ay} $