Physics Elasticity Question 155
Question: A uniform plank of Young’s modulus Y is moved overa smooth horizontal surface by a constant horizontal force F. The area of cross section of the plank is A. The compressive strain on the plank in the direction of the force is
[Kerala PET 2002]
Options:
A) $ F/AY $
B)$ 2F/AY $
C) $ \frac{1}{2}(F/AY) $
D)$ 3F/AY $
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Answer:
Correct Answer: A
Solution:
$ Y=\frac{F/A}{r}\Rightarrow r=\frac{F}{Ay} $