Physics Elasticity Question 156
Question: The mean distance between the atoms of iron is $ 3\times {{10}^{-10}}m $ and interatomic force constant for iron is $ 7,N,/m $ The Young’s modulus of elasticity for iron is
[JIPMER 2002]
Options:
A) $ 2.33\times 10^{5},N/m^{2} $
B) $ 23.3\times 10^{10},N/m^{2} $
C) $ 233\times 10^{10},N/m^{2} $
D)$ 2.33\times 10^{10},N/m^{2} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ Y=\frac{k}{r _{0}}=\frac{7}{3\times {{10}^{-10}}}=2.33\times 10^{10}N/m^{2} $
BETA
