Physics Elasticity Question 164
Question: A rubber cord 10 m long is suspended vertically. How much does it stretch under its own weight (Density of rubber is$ 1500kg/m^{3},Y=5\times 10^{8}N/m^{2},g=10m/s^{2} $ )
[Pb. PET 2001]
Options:
A) $ 15\times 10^{4}m $
B) $ 7.5\times 10^{4}m $
C)$ 12\times 10^{4}m $
D)$ 25\times 10^{4}m $
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Answer:
Correct Answer: A
Solution:
$ l=\frac{L^{2}dg}{2Y}=\frac{{{(10)}^{2}}\times 1500\times 10}{2\times 5\times 10^{8}}=15\times {{10}^{-4}}m $
BETA
