Physics Elasticity Question 168
Question: A material has Poisson’s ratio 0.50. If a uniform rod of it suffers a longitudinal strain of $ 2\times {{10}^{-3}} $ , then the percentage change in volume is
[EAMCET 1987]
Options:
0.6
0.4
0.2
D) Zero
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{dV}{V}=(1+2\sigma )\frac{dL}{L} $
$ \frac{dV}{V}=2\times {{10}^{-3}}=2\times {{10}^{-3}} $
$ \left[ \because \sigma =0.5=\frac{1}{2} \right] $ Percentage change in volume =$ 4\times {{10}^{-1}}=40% $
BETA
