Physics Elasticity Question 18
Question: If a rubber ball is taken at the depth of 200 m in a pool, its volume decreases by 0.1%. If the density of the water is $ 1\times 10^{3},kg/m^{3} $ and $ g=10,m/s^{2} $ , then the volume elasticity in $ N/m^{2} $ will be
[MP PMT 1991]
Options:
A) $ 10^{8} $
B) $ 2\times 10^{8} $
C) $ 10^{9} $
D) $ 2\times 10^{9} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ K=\frac{\Delta P}{\Delta V/V}=\frac{h\rho g}{\Delta V/V}=\frac{200\times 10^{3}\times 10}{0.1/100}=2\times 10^{9} $
BETA
