Physics Elasticity Question 106
Question:Longitudinal stress of $ 1,kg/mm^{2} $ is applied on a wire. The percentage increase in length is $ (Y=10^{11},N/m^{2}) $
Options:
A) 0.002
B) 0.001
C) 0.003
D) 0.01
Show Answer
Answer:
Correct Answer: B
Solution:
Longitudinal strain $ \frac{l}{L}=\frac{r}{Y}=\frac{10^{6}}{10^{11}}={{10}^{-5}} $ Percentage increase in length $ ={{10}^{-5}}\times 100=0.001% $
BETA
