Physics Elasticity Question 28
Question: To break a wire, a force of $ 10^{6},N/m^{2} $ is required. If the density of the material is $ 3\times 10^{3},kg/m^{3} $ , then the length of the wire which will break by its own weight will be
[Roorkee 1979; DPMT 2004]
Options:
A) 34 m
B) 30 m
C) 300 m
3 m
Show Answer
Answer:
Correct Answer: A
Solution:
$ L=\frac{P}{dg}=\frac{6}{3\times 10^{3}\times 10}=\frac{6}{3\times 10^{4}}=2\times 10^{-4}m $
BETA
