Physics Elasticity Question 32
Question: There are two wires of same material and same length while the diameter of second wire is 2 times the diameter of first wire, then ratio ofextension produced in the wires by applying same load will be
[DCE 2000; Roorkee 2000; DCE 2003]
Options:
A) 1 : 1
B) 2 : 1
C) 1 : 2
D) 4 : 1
Show Answer
Answer:
Correct Answer: D
Solution:
$ l=\frac{FL}{AY} $ \ $ l\propto \frac{1}{r^{2}} $ (F, L and Y are constant) $ \frac{l _{1}}{l _{2}}={{\left( \frac{r _{2}}{r _{1}} \right)}^{2}}={{(2)}^{2}}=4 $