Physics Elasticity Question 32

Question: There are two wires of same material and same length while the diameter of second wire is 2 times the diameter of first wire, then ratio ofextension produced in the wires by applying same load will be

[DCE 2000; Roorkee 2000; DCE 2003]

Options:

A) 1 : 1

B) 2 : 1

C) 1 : 2

D) 4 : 1

Show Answer

Answer:

Correct Answer: D

Solution:

$ l=\frac{FL}{AY} $ \ $ l\propto \frac{1}{r^{2}} $ (F, L and Y are constant) $ \frac{l _{1}}{l _{2}}={{\left( \frac{r _{2}}{r _{1}} \right)}^{2}}={{(2)}^{2}}=4 $



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