Physics Elasticity Question 57
Question: A wire is suspended by one end. At the other end a weight equivalent to 20 N force is applied. If the increase in length is 1.0 mm, the increase in energy of the wire will be
Options:
A) 0.01 J
B) 0.02 J
C) 0.04 J
D) 1.00 J
Show Answer
Answer:
Correct Answer: A
Solution:
Increase in energy $ =\frac{1}{2}\times 20\times 1\times {{10}^{-3}}=0.01J $
BETA
