Physics Elasticity Question 68
Question: The work per unit volume to stretch the length by 1% of a wire with cross sectional area of $ 1,mm^{2} $ will be. $
[Y=9\times 10^{11},N/m^{2}] $ [RPET 1999]
Options:
A) $ 9\times 10^{11},J $
B)$ 4.5\times 10^{7},J $
C) $ 9\times 10^{7}J $
D)$ 4.5\times 10^{11},J $
Show Answer
Answer:
Correct Answer: B
Solution:
$ U=\frac{1}{2}\times Y\times {{(r)}^{2}}=\frac{1}{2}\times 9\times 10^{11}\times {{\left( \frac{1}{100} \right)}^{2}} $
$ =4.5\times 10^{7}\ J $
BETA
