Physics Elasticity Question 70
Question: A wire suspended vertically from one of its ends is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 1 mm Then the elastic energy stored in the wire is
[AIEEE 2003]
Options:
A) 0.1 J
B) 0.2 J
C) 10 J
D) 20
Show Answer
Answer:
Correct Answer: A
Solution:
$ U=\frac{1}{2}\times F\times l=\frac{1}{2}\times 200\times {{10}^{-3}}=0.1\ J $
BETA
