Physics Elasticity Question 80
Question: The area of cross-section of a wire of length 1.1 metre is 1 mm2. It is loaded with 1 kg. If Young’s modulus of copper is $ 1.1\times 10^{11},N/m^{2} $ , then the increase in length will be (If $ g=10,m/s^{2}) $
[MP PET 1989]
Options:
A) 0.01 mm
B) 0.075 mm
C) 0.1 mm
D) 0. 15 mm
Show Answer
Answer:
Correct Answer: C
Solution:
$ l=\frac{mgL}{AY}=\frac{1\times 10\times 1.1}{1.1\times 10^{11}\times {{10}^{-6}}}m=0.1\ mm $
BETA
