Physics Elasticity Question 90
Question: The Young’s modulus of a rubber string 8 cm long and density $ 1.5,kg/m^{3} $ is $ 5\times 10^{8},N/m^{2} $ , is suspended on the ceiling in a room. The increase in length due to its own weight will be
[AIIMS 1986]
Options:
A) $ 9.6\times {{10}^{-5}},m $
B) $ 9.6\times {{10}^{-11}},m $
C) $ 9.6\times {{10}^{-3}},m $
D) 9.6 m
Show Answer
Answer:
Correct Answer: B
Solution:
$ l=\frac{L^{2}dg}{2Y}=\frac{{{(8\times {{10}^{-2}})}^{2}}\times 1.5\times 9.8}{2\times 5\times 10^{8}} $
$ =9.6\times {{10}^{-11}}m $
BETA
