Physics Elasticity Question 96

Question: Steel and copper wires of same length are stretched by the same weight one after the other. Young’s modulus of steel and copper are $ 2\times 10^{11},N/m^{2} $ and $ 1.2\times 10^{11},N/m^{2} $ . The ratio of increase in length

[MP PET 1984]

Options:

A) $ \frac{2}{5} $

B) $ \frac{3}{5} $

C) $ \frac{5}{4} $

D) $ \frac{5}{2} $

Show Answer

Answer:

Correct Answer: B

Solution:

$ l=\frac{FL}{AY}\Rightarrow \frac{l _{S}}{l _{cu}}=\frac{Y _{cu}}{Y _{S}} $ (F,L and Y are constant)\ $ \frac{l _{s}}{l _{cu}}=\frac{1.2\times 10^{11}}{2\times 10^{11}}=\frac{3}{5} $



sathee Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on

Please select your preferred language
कृपया अपनी पसंदीदा भाषा चुनें