Physics Elasticity Question 99
Question: The temperature of a wire of length 1 metre and area of cross-section $ 1,cm^{2} $ is increased from 0°C to 100°C. If the rod is not allowed to increase in length, the force required will be $ (\alpha ={{10}^{-5}}/{}^\circ C $ and $ Y=10^{11},N/m^{2}) $
[NCERT 1976; CPMT 1982, 91]
Options:
A) $ 10^{3}N $
B) $ 10^{4}N $
C) $ 10^{5}N $
D) $ 10^{9}N $
Show Answer
Answer:
Correct Answer: B
Solution:
$ F= $ force developed$ =YA\alpha (\Delta \theta ) $
$ =10^{11}\times {{10}^{-4}}\times {{10}^{-5}}\times 100=10^{4}N $
BETA
